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A 12 ohm resistor and a 0.21 henry induc...

A `12 ohm` resistor and a `0.21` henry inductor are connected in series to an `AC` source operating at 20volts,` 50` cycle/second. The phase angle between the current and the source voltage is

A

`30^(@)`

B

`40^(@)`

C

`80^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
` phi = tan^(-1) ((X_(L))/(R)) = tan^(-1) (( 2 pi xx 50 xx 0.21)/(12))`
`rArr phi = 79.68 ~~ 80^(@)`
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