A `200V` ac source is applied in a LCR series circuit which consists of an inductive reactance of `50Omega` a capacitive reactance of `50Omega` and the resistance of `10 Omega` The potential difference across the resistance is .

Options

A. 8 V
B. 10 V
C. 22 V
D. 52 V

Answer

A

Explanation

` Z = sqrt(R^(2) + (X_(L) - X_(C))^(2))= sqrt(3^(2) + (15 - 11) ^(2))= 5 Omega `
`i = (V)/(Z) = (10)/( 5) = 2A`
`V_(R) = i R = 6 V `
`V_(L) = i X_(L) = 2 xx 15 = 30 V `
`V_(C) = i X _(C) = 2 xx 11 = 22 V `
`V_(L) - V_(C) = 30 - 22 = 8 V `