A series circuit connected across a `200 V, 60 Hz` line consists of a capacitive reactance `30 Omega` non inductive resistor of `44 Omega` and a coil of inductive reactance `90 Omega` and resistance `36 Omega` as shown in the diagram

The power used in the circuit is

Options

A. 320W
B. 176W
C. 144W
D. 0W

Answer

C

Explanation

Impedance
`Z = sqrt((R_(1) + R_(2))^(2) + (X_(L) X_(C))^(2))`
`= sqrt((44 + 36 )^(2) + (90 - 30)^(2)) = 100 Omega `
Current `i = (V)/(Z) = (200)/(100) = 2A `
Power dissipated in the coil
`P = I^(2) R = (2)^(2) 36 = 144` Watt