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In any AC circuit the emf (e) and the cu...

In any `AC` circuit the emf `(e)` and the current `(i)` at any instant are given respectively by `e= E_(0)sin omega t`
`i=I_(0) sin (omegat-phi)`
The average power in the circuit over one cycle of `AC` is

A

`(E_(0) I_(0))/(2) cos phi`

B

`E_(0)I_(0)`

C

`(E_(0) I_(0))/(2)`

D

`(E_(0)I_(0))/(2) sin phi`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_("aug") = (V_(0) I_(0))/( 2) cos phi = (E_(0) I_(0))/( 2) cos phi`
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