A `100 Omega` resistance and a capacitor of `100 Omega` reactance are connected in series across a `220` V source. When the capacitor is `50%` charged, the peak value of the displacement current is

Options

A. `11 sqrt(2) A`
B. `2.2 A`
C. 11A
D. 4.4 A

Answer

B

Explanation

`Z = sqrt(R^(2) + X_(C)^(2)) = sqrt((100)^(2) + (100)^(2)) = 100 sqrt(2)`
`I_(max) = (V_(max))/( Z) = (220 sqrt(2))/(100 sqrt(2)) = 2.2 `