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An AC voltage is applied to a resistance...

An `AC` voltage is applied to a resistance `R` and an inductance `L` in series. If `R` and the inductive reactance are both equal to `3 Omega`, the phase difference between the applied voltage and the current in the circuit is

A

Zero

B

`pi//6`

C

`pi//4`

D

`pi//2`

Text Solution

Verified by Experts

The correct Answer is:
C

` phi = tan ^(-1) ((X_(L))/(R)) = tan ^(-1) ((3)/( 3)) = pi // 4`
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