The ratio of the de-Broglie wavelengths of an electron of energy 10 eV to that of a person of mass 66kg traveling with a speed of `100km//h` is of the order of

Options

A. `10^(34)`
B. `10^(27)`
C. `10^(17)`
D. `10^(-10)`

Answer

B

Explanation

`lamda_e =h/(sqrt(2mk))`
and `lamda_("person")=h/(mv)`
`lamda_e/lamda_("person")=(mv)/(sqrt(2mk))=( 66xx100 xx5/18)/(sqrt(2 xx9.1 xx10^(-19)))`
`= 1.07 xx10^(27)`