Find the ratio of kinetic energy of the particle to the energy of the photon , if the de Broglie wavelength of a particle moving with a velocity `2.25xx10^8` m/s is equal to the wavelength of photon .

Options

A. `1//8`
B. `3//8`
C. `5//8`
D. ` 7//8`

Answer

B

Explanation

`lamda=h/(mv) and K_("particle")=1/2mv^2`
`implies K_("particle") = (vh)/(2lamda)`
`K_("photon") = (hc)/lamda`
`(K_("particle"))/(K_("photon"))=v/(2c)=(2.25 xx10^8)/(2xx3 xx10^8) =3/8`