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The graph between the energy log E of a...

The graph between the energy log E of an electron and its de-Broglie wavelength `loglambda` will be

A

B

C

D

Text Solution

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The correct Answer is:
C
`lamda = 1/(sqrt(2mE))implies log lamda=log""h/(sqrt(2m))+log""1/sqrtE`
`implies loglamda=-1/2logE+log""h/(sqrt(2m))`
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