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If the energy of the photon is increased...

If the energy of the photon is increased by a factor of `4` , then its momentum

A

Does not change

B

Decreases by a factor of 4

C

Increases by a factor of 4

D

Decreases by a factor of 2

Text Solution

Verified by Experts

The correct Answer is:
C
Momentum `(p)=E/c , prop E implies p_1/p_2 =E_1/E_2`
`implies (P_1)/(p_2) =E_1/(4E_1)impliesp_2=4p_1`
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