In a photoelectric experiment for 4000 `Å` incident radiation, the potential difference to stop the ejection is 2V. If the incident light is changed to 3000 `Å`, then the potential required to stop the ejection of electrons will be

Options

A. 2 V
B. Less than 2 V
C. Zero
D. Greater than 2 V

Answer

D

Explanation

Since, `K_("max") = (hc)/(lamda)-(hc)/(lamda_0)implieseV_0 = (hc)/(lamda)-(hc)/(lamda_0)`
As `lamda` decreases, `V_0` increases.