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Threshold wavelength for a metal having work function `w_(0)` is `lambda`. Then the threshold wavelength for a metal having work function `2 w_(0)` is

A

`4lamda_0`

B

`2lamda_0`

C

`lamda_0//2`

D

`lamda_0//4`

Text Solution

Verified by Experts

The correct Answer is:
B
`phi_0 = (hc)/(lamda_0) implies phi_0 prop 1/lamda_0`
`W_0/(W_0//2)=(lamda_(0_1))/lamda_0implies lamda_(0_1)=2lamda_0`
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