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Light of wavelength 1824 Å, incident on ...

Light of wavelength `1824 Å`, incident on the surface of a metal , produces photo - electrons with maximum energy `5.3 eV`. When light of wavelength `1216 Å` is used , maximum energy of photoelectrons is `8.7 eV`. The work function of the metal surface is

A

`3.5 eV`

B

`13.6eV`

C

`6.8 eV`

D

`1.5 eV`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_("max")=E=phi_0`
`5.3 eV = (hc)/lamda-phi_0=(12375)/(1824)=6.78eV`
`implies phi_0 = 6.78 - 5.3 = 1.48 eV ~~1.5 eV`
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