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The threshold frequency for a metallic s...

The threshold frequency for a metallic surface corresponds to an energy of `6.2eV` and the stopping potential for a radiation incident on this surface is `5 V` . The incident radiation lies in

A

Infra-red region

B

Visible region

C

X-ray region

D

Ultra-violet region

Text Solution

Verified by Experts

The correct Answer is:
D
`K_("max") = (hc)/(lamda) -phi_0`
`implies (hc)/lamda=5eV+6.2eV =11.2eV`
`lamda(Å )=(12400)/(11.2(eV))=1107Å`
Wavelength lies in ultraviolet region.
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