The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1MeV energy is nearly

Options

A. 1.2nm
B. `1.2 xx10^(-3) nm`
C. `1.2 xx10^(-6) nm`
D. `1.2 xx10` nm

Answer

B

Explanation

Given in the question
Energy of a photon, E = 1MeV `implies 10^6 eV`
Now, hc = 1240 eVnm
Now , `E = (hc)/lamda`
`implies lamda = (hc)/E = (1240eVnm)/(10^6 eV) = 1.24 xx10^(-3)nm`