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The maximum velocity of an electron emit...

The maximum velocity of an electron emitted by light of wavelength `lambda` incident on the surface of a metal of work function `phi`, is
Where h = Planck's constant , m = mass of electron and c = speed of light.

A

`[(2(hc+lamdaphi))/(mlamda)]^(1//2)`

B

`(2(hc-lamdaphi))/(mlamda)`

C

`[(2(hc-lamdaphi))/(mlamda)]^(1//2)`

D

`[(2(hlamda-phi))/m]^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`1/2mv_m^2=(hc)/lamda-phi`
`impliesv_(m) =[(2(hc-lamdaphi))/(mlamda)]^(1/2)`
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