A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of`3xx10^6 ms^-1`. The velocity of the particle is:(Mass of electron=`9.1 xx 10^-31`kg)

Options

A. `3 xx10^(-31) ms^(-1)`
B. `2.7 xx10^(-21) ms^(-1)`
C. `2.7 xx10^(-18) ms^(-1)`
D. `9 xx10^(-2) ms^(-1)`

Answer

C

Explanation

`lamda = h/(mv)`
Since, `lamda_p = lamda_eimplies m_pv_p =m_ev_e`
`implies v_p = (9.1 xx10^(-31) xx 3xx10^6 )/(10^(-6))=2.7 xx10^(-18)m//s`