The wavelength `lamda_(e)` of an electron and `lamda_(p)` of a photon of same energy E are related by

Options

A. `lamda_p prop lamda_e`
B. `lamda_p prop lamda_e^2`
C. `lamda_p prop sqrt(lamda_e)`
D. `lamda_p prop 1/sqrt(lamda_e)`

Answer

B

Explanation

For electron –
`lamda_e = h/(mv) = (h)/(sqrt(2mK))`
For photon –
`K=(hc)/(lamda_(ph)):. lamda_e^2=(h^2lamda_(ph))/(2m(hc))`
`implies lamda_e^2prop lamda_(ph)`