When the mkomentum of a proton is changed by an amount `p_(0)`, the corresponding change in the de-Broglie wavelength is found to be `0.25%`. Then, the original momentum of the proton was

Options

A. `P_0`
B. `100 P_0`
C. `400 P_0`
D. ` 4P_0`

Answer

C

Explanation

`lamda = h/P implies lamda prop 1/P`
`implies |(Deltalamda)/(lamda)|=|(DeltaP)/(P)|impliesP_0/P=(0.25)/(100)impliesP=400P_0`