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The de-Broglie wavelength of neutron in ...

The de-Broglie wavelength of neutron in thermal equilibrium at temperature T is

A

`(3.08)/sqrtTÅ`

B

`(0.308)/sqrtTÅ`

C

`(0.0308)/sqrtTÅ`

D

`(30.8)/sqrtTÅ`

Text Solution

Verified by Experts

The correct Answer is:
D
`lamda=h/(sqrt(2mkT))=(6.6xx10^(-34))/(sqrt(2xx1.67 xx10^(-27)xx1.38 xx10^(-23)T))`
`implies lamda = (30.8)/sqrtTÅ`
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