When photons of energy `hv` fall on an aluminium plate (of work function `E_(0)`), photoelectrons of maximum kinetic energy `K` are ejected . If the frequency of the radiation is doubled , the maximum kinetic energy of the ejected photoelectrons will be

Options

A. K
B. `K+hv`
C. `K+E_0`
D. 2K

Answer

B

Explanation

`K = hv -f_0" " …(i)`
`K. = 2hn -phi_0 = hv + K" " …(ii)`
From (i) and (ii)
`K. = K + hv` .