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A beam of 350 keV electrons a molybdenum...

A beam of 350 keV electrons a molybdenum target, generating the X-rays. What is the cut-off wavelength?

A

35.5 pm

B

40.0 pm

C

15.95 pm

D

18.2 pm

Text Solution

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The correct Answer is:
A
`lamda_("min")(Å) = (hc)/(k(eV))=((4.14 xx10^(15))(3xx10^8))/(35 xx10^(3))`
`=35.5 xx10^(-12) m =35.5 `pm
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