An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is `1.227 xx 10^(-2)` nm, the potential difference is:

Options

A. 10 V
B. `10^2V`
C. `10^3V`
D. `10^4V`

Answer

D

Explanation

`lamda = 1.227 xx10^(-2)nm`
`= 0.1227 Å`
`lamda = (12.27)/sqrtV Å`
0.1227 `= (12.27)/sqrtV Å`
`sqrtV = 10^2 implies V = 10^4` volt.