Three liquids of equal masses are taken in three identical cubical vessels A,B and C. Their densities are `rho_(A),rho_(B)` and `rho_(C)` respectively but `rho_(A)ltrho_(B)ltrho_(C)`. The force exerted by the liquid on the base of the cubical vessel is

Options

A. Maximum in vessel C
B. Minimum in vessel C
C. The same in all the vessels
D. Maximum in vessel A

Answer

C

Explanation

`P=rho gh`
`rho=("Mass")/("Volume")=(m)/(Ah) implies h= (m)/(rho xx A)`
`:. P=rho g xx (m)/(rho xx A)=(mg)/(A)`
Force `F=P xx A= (mg)/(A) xx A = mg`
`m_A =m_B=m_C implies F_A = F_B=F_C`