The force acting on a window of area `50cm xx 50cm` of a submarine at a depth of `2000 m` in an ocean, the interior of which is maintained at sea level atmospheric pressure is (Density of sea water = `10^(3)kgm^(-3)`, `g = 10ms^(-2)`)

Options

A. `10^6 N`
B. `5xx10^5 N`
C. `25xx10^6` N
D. `5xx10^6 N`

Answer

D

Explanation

Pressure outside the submarine = `P = P_a+rho gh` [`P_a rarr` atm]
Pressure inside the submarine = `P_a`
Net pressure acting on window (Gauge pressure)
`P_g=P-P_a=rho gh=10^3 xx10xx2000`
Force (F) = `P_g xx A=2xx10^7 xx 2500xx10^(-4)`
= `5xx10^6` N.