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On a new scale of temperature (which is ...

On a new scale of temperature (which is linear) and called the `W` scale. The freezing and boiling points of water are `39^(@)W` and `239^(@)W` respectively. What will be the temperature on the new scale, corresponding to a temperature of `39^(@)C` on the Celsius scale?

A

`200^@ W`

B

`139^@ W`

C

`78^(@) W`

D

`117^(@)W`

Text Solution

Verified by Experts

The correct Answer is:
D
`(T_C)/(100) = (W-39)/(239-39) rArr (39)/(100) = (W-39)/(200)`
`rArr 39 xx 2 + 39 = W rArr W = 117^@`.
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