22320 cal of heat is supplied to 100 g of ice at `0^(@)C`. If the latent heat of fusion of ice is `80cal g^(-1)` and latent heat of vaporization of water is `540cal g^(-1)`, the final amount of water thus obtained and its temperature respectively are

Options

A. `8g 100^(@) C`
B. `100 g , 90^@C`
C. `92 g, 100^(@)C`
D. `80g, 100^@C`

Answer

C

Explanation

`underset((0^@C))(Ice) overset(Lr) rarr underset((0^@C))(Water ) overset(Qs)underset(Heat)rarr underset((100^@C))"Water" overset(Lv)rarrunderset((100^@C))"Steam"`
`Q = L_i + Q_s + L_v = m.L_(f) + mSDelta T + m xx 540`
`rArr 22320 = 100 xx 80 + 100 xx 1(100-0) + mxx 540`
`rArr m. = 8g`
Mass of vapour = 8g
Amount of water = 100-8 = 92 g.