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Work done in converting 1 g of ice at -1...

Work done in converting 1 g of ice at `-10^@C` into steam at `100^@C` is

A

3045 J

B

6056 J

C

721 J

D

616 J

Text Solution

Verified by Experts

The correct Answer is:
A
`Q = m_(i)s_(i)Delta T + mL_(f) + m_(w)s_(w) Delta T+mL_(v)`
`= 1 xx 0.5 xx 10 + 1 xx 80 + 1 xx 1 (1000 - 0) + 1 xx 540`
= 725 cal
Work done (W) `= 4.2 xx 725`
`= 3045 J`.
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