`50 gm `of copper is heated to increase its temperature by `10^(@)C.` If the same quantity of heat is given to `10 gm `of water, the rise in its temperature is (Specific heat of copper`=420 Joule-kg^(-1)@C^(-1)`

Options

A. `5^@ C`
B. `6^@ C`
C. `7^@ C`
D. `8^@C`

Answer

A

Explanation

`Q_(Cu) = m_(cu)S_(cu) Delta = 50 xx 10^(-3) xx 420 xx 10 = 42 xx 5`
Now, `m_(w)s_(w) Delta T =42 xx 5`
`Delta T= (42 xx 5)/(10 xx 10^(-3) xx 4200) = 5^@C`