An experiment takes `10` minutes to raise the temperature of water in a container from `0^(@)C "to" 100^(@)C` and another `55` minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking specific heat of water to be `1 "cal//g ^(@)C`, the heat of vapourization according to this experiment will come out to be:-

Options

A. 530 cal/g
B. 540 cal/g
C. 550 cal/g
D. 560 cal/g

Answer

C

Explanation

Heat given per second `= (m xx 1 xx 100)/(10 xx 60)` cal
Now , Q = mL
Heat supplied per sec to steam ` = (mL)/(55 xx 60)`
`therefore (mxx1xx100)/(10 xx 60) = (mL)/(55 xx 60)`
`rArr L = 550 cal//g`.