Speed of sound waves in air

Options

A. Is independent of temperature
B. Increase with pressure
C. Increases with increase in humidity
D. Decrease with increase in humidity

Answer

C

Explanation

Due to presence of moisture density of air decreases, we know that speed of sound in air is given by
`v=sqrt((gammaP)/(rho))`
For air `gamma` and P are constants
`vprop(1)/(sqrt(rho))`, where `rho` is density of air.
`(v_(2))/(v_(1))=sqrt((rho_(1))/(rho_(2)))`
Where `rho_(1)` is density of dry air and `rho_(2)` is density of moist air.
As `rho_(2)ltrho_(1)=(v_(2))/(v_(1))gt1impliesv_(2)gtv_(1)`
Hence, speed of sound wave in air increases with increase in humidity.