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The stationary wavey = 2a sin kx cos ome...

The stationary wave`y = 2a sin kx cos omega t` in a closed organ pipe is the result of the superposition of `y = a sin (omega t - kx)`

A

`y=-acos(omegat+kx)`

B

`y=-asin(omegat+kx)`

C

`y=asin(omegat+kx)`

D

`y=acos(omegat+kx)`

Text Solution

Verified by Experts

The correct Answer is:
B
For closed organ pipe (for Rigid boundary)
`y_(i)=asin(omegat-kx)`
Reflected wave -
`y_(R)=-asin(omegat+kx)`.
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