If the speed of the wave shown in the figure is `330m//s` in the given medium then the equation of the wave propagating in the positive x-direction will be (all quantities are in M.K.S units)

Options

A. y = 0.05 sin `2pi` (4000t - 12.5x)
B. y = 0.05 sin `2pi` (4000t-122.5x)
C. y = 0.05 sin `2pi` (3300t - 10x)
D. y = 0.05 sin `2pi` (3300x - 10t)

Answer

C

Explanation

`A=0.05m, (5lambda)/(2)=0.25implieslambda=0.1`
Since, `v=lambda fimpliesf=(330)/(0.1)=3300`
and `k=(2pi)/(lambda)=(2pi)/(0.1)=(10)xx2pi`
`therefore y=0.05sin2pi(3300t-10x)`.