A wave travelling in positive X-direction with `A=0.2m` has a velocity of `360m//sec` . If `lambda=60m` , then correct expression for the wave is

Options

A. `y=0.2sin[2pi(6t+(x)/(60))]`
B. `y=0.2sin[pi(6t+(x)/(60))]`
C. `y=0.2sin[2pi(6t-(x)/(60))]`
D. `y=0.2sin[pi(6t-(x)/(60))]`

Answer

C

Explanation

`A=0.2m, v=360m//sec`
`lambda=60mimpliesk=(2pi)/(lambda)=(2pi)/(60)=(pi)/(30)`
`v=lambdafimpliesf=(360)/(60)=6Hz`
`omega=2pif=12pi`
`y=Asin(omegat-kx)`
`implies y=0.2sin(12pit-(pix)/(30))`
`impliesy=0.2sin[2pi(6t-(x)/(60))]`.