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The wavelength of a wave in a medium is 0.5 m. The phase difference between the oscillations at two points in the medium due to this wave is `(pi)/(5)`. What is the minimum distance between these points

A

0.05 m

B

0.1 m

C

0.25 m

D

0.15 m

Text Solution

Verified by Experts

The correct Answer is:
A

`Deltaphi=(2pi)/(lambda)xxDeltax`
`implies Deltax=(lambda)/(2pi)xxDeltaphi=(lambda)/(2pi)xx(pi)/(5)=(0.5)/(10)=0.05`.
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