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A wave of frequency 500 Hz has velocity ...

A wave of frequency 500 Hz has velocity 360 m/sec. The distance between two nearest points `60^(@)` out of phase, is

A

0.6 cm

B

12 cm

C

60 cm

D

120 cm

Text Solution

Verified by Experts

The correct Answer is:
B
`Deltaphi=(2pi)/(lambda)xxDeltax`
`Deltax` = path difference `=(lambda)/(2pi)xx(pi)/(3)=(lambda)/(6)implieslambda=6Deltax`
Since, `v=flambda=f(6Deltax)`
`therefore Deltax=(360)/(6xx500)=0.12m=12cm`.
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