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Two loudspeakers L1 and L2 driven by a c...


Two loudspeakers `L_1` and `L_2` driven by a common oscillator and amplifier, are arranged as shown. The frequency of the oscillator is gradually increased from zero and the detector at D records a series of maxima and minima. If the speed of sound is `330ms^-1` then the frequency at which the first maximum is observed is

A

165 Hz

B

330 Hz

C

496 Hz

D

660 Hz

Text Solution

Verified by Experts

The correct Answer is:
B
Path difference
`Deltax=L_(2)D-L_(1)D`

`implies Deltax=sqrt(40^(2)+9^(2))-40=1m`
for `1^(st)` maxima.
`Deltax=2nlambda//2,n` is an integer
`1=2(1)(lambda)/(2)implieslambda=1m`
`therefore f=(v)/(lambda)=330Hz`.
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