The frequency of a stretched uniform wire under tension is in resonance with the fundamental frequency of a closed tube. If the tension in the wire is increased by 8 N , it is in resonance with the first overtone of the closed tube. The initial tension in the wire is

Options

A. 1 N
B. 4 N
C. 8 N
D. 16 N

Answer

A

Explanation

`(1)/(2l)sqrt((T)/(mu))=(v)/(4l)...(i)`
and `(1)/(2l)sqrt((T+8)/(mu))=(3v)/(4l)...(ii)`
from (i) and (ii)
`sqrt((T)/(T+8))=(1)/(3)impliesT=1N`.