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A source and an observer approach each other with same velocity 50 m/s . If the apparent frequency is `435 sec^( –1)`, then the real frequency is

A

`320sec^(-1)`

B

`360sec^(-1)`

C

`390sec^(-1)`

D

`420sec^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`f.=f((v+v_(o))/(v-v_(s)))implies435=f((332+50)/(332-50))`
`implies f=321.2sec^(-1)~~320sec^(-1)`.
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