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A source and an observer move away from each other with a velocity of 10 m/s with respect to ground. If the observer finds the frequency of sound coming from the source as 1950 Hz , then actual frequency of the source is (velocity of sound in air = 340 m/s )

A

1950 Hz

B

2068 Hz

C

2132 Hz

D

2486 Hz

Text Solution

Verified by Experts

The correct Answer is:
B

`f.=f((v-v_(o))/(v+v_(s)))`
`implies 1950=f((340-10)/(340+10))`
`implies f=1950xx(350)/(330)=2068Hz`.
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