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Two sources A and B are sounding notes of frequency 680 Hz. A listener moves from A to B with a constant velocity u. If the speed of sound is 340 m/s, What must be the value of u so that he hears 10 beats per second?

A

4

B

8

C

2

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
`f_("beat")=(2fv_(o))/(v_("sound"))=(2xx660xx1)/(330)=4`.
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