In a guitar , two strings A and b made of same material are slightly out of tune and produce beats of frequency 6 Hz. when tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency od A is 530 hz, the original frequency of B will be

Options

A. 523 Hz
B. 524 Hz
C. 536 Hz
D. 537 Hz

Answer

C

Explanation

Guitar string i.e., string is fixed from both ends

Frequency `propsqrt("Tension") (because n=(1)/(2l)sqrt((T)/(m)))`
If tension in B slightly decrease then frequency of B decrease.
If B is 536Hz , as the frequency decreases, beats with A also decreases.
If B is 524Hz , as the frequency decreases, beats with A increases
`therefore` Original frequency of B will be 524Hz .