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The magnetic field dvecB due to a small ...

The magnetic field `dvecB` due to a small current element `dvecl` at a distance `vecr` and element carrying current `i` is,

A

`dvecB = (mu_(0))/(4pi) ((dvecl xx vecr)/( r))`

B

`dvecB = (mu_(0))/(4pi) ""i^(2) ((dvecl xx vecr)/( r))`

C

`dvecB = (mu_(0))/(4pi) ""i^(2) ((d vecl xx vecr)/( r^(2)))`

D

`dvecB = (mu_(0))/(4pi) ""i((dvecl xx vecr)/(r^(3)))`

Text Solution

Verified by Experts

The correct Answer is:
D

`dB = (mu_(0))/(4pi) . (i(dvecl sin theta))/(r^(2)) = (mu_(0))/(4pi) (i(dvecl xx vecr))/(r^(3))`
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