A particle carrying a charge equal to `100` times the charge on an electron is rotating per second in a circular path of radius `0.8 metre`. The value of the magnetic field produced at the centre will be (`mu_(0)=` permeability for vacuum)

Options

A. `(10^(-7))/(mu_(0))`
B. `10^(-17) mu_(0)`
C. `10^(-6) mu_(0)`
D. `10^(-7) mu_(0)`

Answer

B

Explanation

Current (I) = 100 e = `100 xx 1.6 xx 10^(-19) = 1.6 xx 10^(-17) A`
`B_("Centre") = (mu_(0) I)/(2R) = (4pi xx 10^(-7) xx 1.6 xx 10^(-17))/(2 xx 0.8) = 10^(-17) mu_(0)`