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A long solenoid carrying a current prod...

A long solenoid carrying a current produces a magnetic field `B` along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is

A

B

B

2 B

C

4 B

D

B/2

Text Solution

Verified by Experts

The correct Answer is:
A

`B = mu_(0) nI`
`(B_(1))/(B_(2)) = (n_(1))/(n_(2)) xx (I_(1))/(I_(2)) = (1)/((1//2)) xx (1)/(2) implies B_(1) = B_(2) = B`
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