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Two particles X and Y having equal charges, after being accelerated through the same potential difference, enter a region of uniform magnetic field and describe circular path of radius `R_1` and `R_2` respectively. The ratio of mass of X to that of Y is :

A

`((R_(1))/(R_(2)))^(1//2)`

B

`(R_(2))/(R_(1))`

C

`((R_(1))/(R_(2)))^(2)`

D

`(R_(1))/(R_(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

Since , qvB = `(mv^(2))/ (r ) = (mv)/(qB) = sqrt((2mk)/(q^(2) B^(2))) = (1)/(B) sqrt((2mV)/(q))`
`r prop sqrtm implies (m_(1))/(m_(2)) = ((R_(1))/(R_(2)))^(2)`
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