A particle of mass `0.6g` and having charge of `25 nC` is moving horizontally with a uniform velocity `1.2xx10^(4)ms^(-1)` in a uniform magnetic field, then the value of the magnetic induction is `(g=10ms^(-2))`

Options

A. Zero
B. 10 T
C. 20 T
D. 200 T

Answer

C

Explanation

m = 0.6 g , q = `25 xx 10^(-9)C , v = 1.2 xx 10^(4)` m/s
Since , v = constant
`|F_(m)| = mg implies mg = qvB`
`B = (mg)/(qv) = (0.6 xx 10^(-3) xx 10)/(25 xx 10^(-9) xx 1.2 xx 10^(4)) implies B = 20T`