A current carrying loop is free to turn in a uniform magnetic field. The loop will then come into equilibrium when its plane is inclined at

Options

A. `0^(@)` to the direction of the field
B. ` 45^(@)` to the direction of the field
C. `90^(@)` to the direction of the field
D. `135^(@)` to the direction of the field

Answer

C

Explanation

Equilibrium , `vecB|| vecM , theta = 0`
Plane of coil is perpendicular to `vecB`