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Current i is carried in a wire of length...

Current `i` is carried in a wire of length `L`. If the wire is turned into a circular coil, the maximum magnitude of torque in a given magnetic field `B` will be

A

`(LiB^(2))/(2)`

B

`(Li^(2) B)/(2)`

C

`(L^(2) iB)/(4pi)`

D

`(Li^(2) B)/(4pi)`

Text Solution

Verified by Experts

The correct Answer is:
C

`tau = iAB ` , as `r = (L)/(2pi)`
`= (ipi L^(2))/(4pi^(2)) ""B implies T_("max") = (iL^(2) B)/(4pi)`
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