A 100 turns coil shown in figure carries a current of 2 amp in a magnetic field `B=0.2 Wb//m^(2)`. The torque acting on the coil is

Options

A. 0.32 Nm tending to rotate the side AD out of the page
B. 0.32 Nm tending to rotate the side AD into the page
C. 0.0032 Nm tending to rotate the side AD out of the page
D. 0.0032 Nm tending to rotate the side AD into the page

Answer

A

Explanation

`tau = vecM xx vecB = NIAB`
`=100 xx 2 xx (10 xx8) xx 10^(-4) xx 0.2 = 0.32` Nm
F on AD `to` out of page